2-[2(3+x)-3(2-x)]=2

Solution for 2-[2(3+x)-3(2-x)]=2 equation:

Simplifying
2 + -1[2(3 + x) + -3(2 + -1x)] = 2
2 + -1[(3 * 2 + x * 2) + -3(2 + -1x)] = 2
2 + -1[(6 + 2x) + -3(2 + -1x)] = 2
2 + -1[6 + 2x + (2 * -3 + -1x * -3)] = 2
2 + -1[6 + 2x + (-6 + 3x)] = 2

Reorder the terms:
2 + -1[6 + -6 + 2x + 3x] = 2

Combine like terms: 6 + -6 = 0
2 + -1[0 + 2x + 3x] = 2
2 + -1[2x + 3x] = 2

Combine like terms: 2x + 3x = 5x
2 + -1[5x] = 2

Remove brackets around [5x]
2 + -1 * 5x = 2

Multiply -1 * 5
2 + -5x = 2

Add '-2' to each side of the equation.
2 + -2 + -5x = 2 + -2

Combine like terms: 2 + -2 = 0
0 + -5x = 2 + -2
-5x = 2 + -2

Combine like terms: 2 + -2 = 0
-5x = 0

Solving
-5x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-5'.
x = 0

Simplifying
x = 0